solve log 2x + log 12 =3 can someone please explain
write log 2x + log 12 as one log log 2x*12=3 then apply base 10 exponential to both sides, which cancels the log on the left 2x*12=10^3 should be easy now
Do you know your laws of logarithms?
Well the left side can be combined into one log using the law that says \[\log_{a}x+\log_{a}y=\log_{a}xy\]
Right, so that gives us log 2x*12=3 when there is no base written it's the common log with base 10, to cancel a log out you apply that base exponential to both sides, in this case 10 2x*12=10^3
so 10^3 to both sides
No, base 10 exp. to both sides. Before i canceled the log out it would look like this \[10^{\log 2x*12}=10^3\]
right, so the log and the 10 cancel, leaving you with 2x*12=10^3
Can you solve now?
You cant solve 24x=1000?
what happens to the x thats what confuses me
multiply 2*12 to get 24 and 10*10*10 to get 1000 then multiply the two together to get x which would be 24,000
x is what you're solving for... 2*12x=24x 10^3=1000 so, 24x=1000 just divide both sides by 24 and x is solved for
41.67
Yep
thank you for helping
No problem, if you get familiar with these laws of logarithms it makes these problems a lot easier
ok thanks
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