Question

A spinner contains 4 equal sections, one of which is yellow, and the rest are blue. If the spinner is spun 3 times, determine the probability that:
a) it lands on yellow exactly twice
b) it lands on yellow at least twice

Answer 1

please help

Answer 2

OKay, on this I'm trying to figure out, the probability all together is 4/6 right? So simplify that and see what you get!

Answer 3

do you know the prob of getting yellow?

Answer 4

on one spin

Answer 5

no i'm not sure

Answer 6

IN your question it says there's 4 sections, 1 yellow the rest blue, which makes 3 blues, (SOrry I told you differntly earlier)

Answer 7

Do you get that?

Answer 8

ya all are 4 but how u got 6

Answer 9

Sorry, that was wrong!!

Answer 10

I typed the wrong number!

Answer 11

what i did is 2/4 = 1/2 but i'm not sure for my answer

Answer 12

cuz it exactly twice yellow in a

Answer 13

is that true

Answer 14

I" mnot sure, trying to figure it out!

Answer 15

Sorry, I thought I had it, but had to re look

Answer 16

yes please

Answer 17

I would start by answering my question

Answer 18

i need ur help

Answer 19

the prob of getting yellow
is that 2/4 i'm not sure

Answer 20

# of yellow sections/total number of sections

Answer 21

oh it means 1/4

Answer 22

right

Answer 23

yes

Answer 24

what is the prob you don't get yellow then

Answer 25

i didn't get it

Answer 26

ie what is the probability of getting a blue

Answer 27

you will need both of these numbers

Answer 28

3/4

Answer 29

yes

Answer 30

so if you want exactly 2 yellow

that can happen 3 different ways

...

Answer 31

YYB
YBY
BYY

Answer 32

so you need to compute the prob of getting YYB in that order

Answer 33

there is only 1YYB so it means 1/3

Answer 34

no

Answer 35

if each spin is independent then you need to multiply the probabilities of getting Y and Y and B

Answer 36

ie \[\frac{1}{4}\cdot\frac{1}{4}\cdot\frac{3}{4}\]

Answer 37

are you studying the binomial distribution?

Answer 38

no

Answer 39

solving prob problem

Answer 40

ok...this problem follows a binomial distribution...just so you know

Answer 41

so YYB gives \(\displaystyle\frac{3}{64}\)

Answer 42

I assume you have studied independent events.

Answer 43

this is for a right what about b

Answer 44

we are not done with (a)

Answer 45

oh

Answer 46

you still need to do YBY and BYY

Answer 47

it will be 3/64

Answer 48

yes...for each

Answer 49

so what is the prob of getting exactly 2 Yellow?

Answer 50

we add all of it 3/64 + 3/64 + 3/ 64

Answer 51

correct and get 9/64

Answer 52

now we can do part (b)

Answer 53

at least twice means 2 or more times

Answer 54

thnx ya

Answer 55

so we know the prob of exacty 2 ...what is the prob of exactly 3 yellow?

Answer 56

we add on it the same #

Answer 57

it will not be 3/64

Answer 58

YYY

Answer 59

like this

Answer 60

yes

Answer 61

so 3/729

Answer 62

\[\frac{1}{4}\cdot\frac{1}{4}\cdot\frac{1}{4}\]

Answer 63

1/64

Answer 64

yes...now add to our previous result

Answer 65

9/64 + 1/64= 10/ 64

Answer 66

yep

Answer 67

oh thnx I really appreciate that's so helpful

Answer 68

np

Answer 69

can i ask u 1 more quetion i need some one 2 understand me like that