Question

find the absolute value of the complex number
3i-2

Answer 1

Recall: \(|a+bi|=\sqrt{a^2+b^2}\). Try that first! :)

Answer 2

how do u solve?

Answer 3

Using watchmath's formula, the equation 3i-2 would turn into [\sqrt{3^{2}-2^{2}}\]. See if you can solve it from there.

Answer 4

\[\sqrt{3^{2}-2^{2}}\]

Answer 5

be careful JetWave600

Answer 6

a+bi=3i-2 what is a and b here ?

Answer 7

a=3 b=i ?

Answer 8

be careful! b is the number before i and a is the number without i

Answer 9

b=2

Answer 10

@watchmath

Answer 11

lets write 3i-2 so it looks like a+bi. We can write it as -2+3i right? now what is a and b?

Answer 12

3i

Answer 13

@watchmath

Answer 14

a+bi=-2+3i. Can you see what is a and b ?

Answer 15

a=-2 b=3?

Answer 16

thats right , so what is the modulus (absolute value)?

Answer 17

how do i find that

Answer 18

@UnkleRhaukus

Answer 19

well ill draw the diagram, maybe then you'll understand where the formula comes from