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write the slope-intercept form of the equation of the line described: through: (2,-1) parallel to y=-2x+2
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i know that the slope will be the same, since it's parallel.. i just am not sure as to how to find the y-intercept
\[y-(-1)=-2(x-2)\]\[y=-2x+4-1\]\[y=-2x+3\]
is the formula: y-y1=M(x-x1)?
???
for point-intercept, yes. it is.
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okay, thanks. you mind helping me with perpindicular real fast?
sure.
okay thanks. it says: through: (-5,2) perp. to y=-5/3x+1
anyone??
perp means that it's slope is the negative rec. of your other given slope, so plug in the new point and slope, and solve.
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so my slope is now 3/5?
yep.
okay hold on
is 3/5x+1 correct?
no, the slope is correct, but the y-int isn't.
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okay i seee my mistake
y=3/5x+4 ?
still nope
what's the answer?
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