Question

Find the absolute extrema for these functions:
f(x) = x^3 - 3x^2 for [-1,3]

Answer 1

wouldn't max be 2 not 0?

Answer 2

@Hero

Answer 3

first take the derivative and set it equal to 0 to find the critical points. so:
f '(x) = 3x^2 - 6x = 0
0 = x(3x -6)
x=0 , x=2
"candidates for extrema are critical points and endpoints so....
f(0) =0
f(2) = -4
f(-1) = -4
f(3) = 0

Answer 4

ok but wouldn't maximum be 2 not 0?

Answer 5

oh wait nvm lmfao

Answer 6

@TweT226 can u help me with another one pls? ^^

Answer 7

yeah?