Question

(2x)^-2

Answer 1

\[\Large (2x)^{-2} \to \frac{1}{(2x)^2}\to \frac{1}{2^2x^2}\to \frac{1}{4x^2}\]

Answer 2

Ohhh thank you so much!!

Answer 3

No you drop the negative

Answer 4

@4thief : Explain.

Answer 5

@saifoo.khan you're right. It says your answer on the answer sheet

Answer 6

What about (2x/3y) ^-3

Answer 7

Try it out!

Answer 8

I did. But I get like 6 and 9 for the numbers but the answer is like 27 and 8

Answer 9

Where does the 27 come from..?

Answer 10

What will be the first step?

Answer 11

Umm put the -3 on the bottom?

Answer 12

No.
Whenever you get a problem with a negative exponent, always flip the fraction. This should be your first step.

Answer 13

Oh. Okay so 3y/2x but what about the 3?

Answer 14

Shouldn't it be 9y^3/6x^3

Answer 15

Now 3 stays the positive.