If you deposit $1,000 into an account that pays 4% interest compounded continuously, how long will it take the account to grow to $2,000?
is 19 months correct? if so is there a formula to figure this out?
\[2=e^{.04t}\] solve for \(t\)
oh hell no, it is several years, approximately \(\frac{72}{4}=18\) although it is probably a bit shorter
oh okay, somebody told me 19 months
can you help me work the problem out? @satellite73
ok you are asked for how long it take your money to double from 1000 to 2000 for continuous compounding use \[P_0e^{rt}\] in your case \(r=.04,P_0=1000\) so solve \[2000=1000e^{.04t}\] for \(t\)
first step is divide by 1000 and get \[2=e^{.04t}\] then in equivalent logarithmic form this is \[.04t=\ln(2)\] so \[t=\frac{\ln(2)}{.04}\]
18 was an over estimate i got from the rule of 72 real answer is a bit over 17 http://www.wolframalpha.com/input/?i=ln%282%29%2F.04
you have helped me so much with this, thank you thank you!!
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