Question

Weird integral problem.
See below.

Answer 1

what is f(x) you have two different equations up there

Answer 2

for some reason I'm betting it is \(f(x)=x^2-2x+2\)

Answer 3

it integrates to 48 and it gives one of the above as an answer to his specific question

Answer 4

but it says using three rectangles. i tried summation and got a huge number

Answer 5

you have to use riemann's sum.

Answer 6

lower sums also

Answer 7

if you put up what the actual equation is, then maybe we could help. what is f(x)?

Answer 8

sorry not good with words, is that the summation thingy?

Answer 9

what do u mean actual equation?
as in F(x) = x^3/3 -x^2 +x ?

Answer 10

the antiderivative?

Answer 11

nono, I am confused because you gave us two different functions. x^2-x+1 and x^2-2x+1.

Answer 12

scroll up and you will see what I mean. what equation are you trying to find the integral of.

Answer 13

x^2-2x+1?

Answer 14

yeah thats the right one

Answer 15

this that function if you actually integrate you dont get 48 like you said above

"i got the actual integral to be 48 "

Answer 16

the answer is 106/3 lol

Answer 17

wow what a bad sentence ;) on my part

Answer 18

I integrated, and i got 106/3. Odd. Double check again what the equation is please.

Answer 19

nvm i asked my friend got it.

Answer 20

what was the answer?

Answer 21

26

Answer 22

interesting...that answer corresponds to \[f(x)=x^2-2x+2\] ;)

Answer 23

Typos make math impossible to figure out xD

Answer 24

sorry.

Answer 25

wait i'm still not getting the answer

Answer 26

? what do you mean?

Answer 27

If
\[\int\limits_{0}^{6} (x^2-2x+2)dx\]
is approximated by three inscribed rectangles of equal width, then the approximation is...
A) 21
B) 26
C) 28
D) 48
E) 76

this is the actual problem

Answer 28

so i got
\[\frac{ 6 }{ 3 } \sum_{i = 1}^{6} (x^2-2x+2)\]

Answer 29

but the answer i got was 584