Find the molar mass of AgNO3 given the following atomic masses: AG = 107.9 u, N = 14.01 u, O = 16.00 u. Remember to round to proper significant figures

Question

nottim · Answer

What formula(s) relate to this question?

anonymous · Answer

$$AgNO _{3}$$

nottim · Answer

No, 'mathematical' formulas.

anonymous · Answer

nope all the info I was given is in the question above

nottim · Answer

You don't have a formula sheet? Or liek a textbook with the formulas?

anonymous · Answer

What it has is an example problem but I don't see any formula.

Do you want the example problem?

nottim · Answer

http://www.docbrown.info/page04/4_73calcs/moleformula.gif http://www.chemistryrules.me.uk/middle/triangle1_c.gif

nottim · Answer

Something like that?

anonymous · Answer

I don't have anything like that. O_o

nottim · Answer

oh.

nottim · Answer

Anyways, first add all the atomic masses together (do remember to multiply oxygen's atomic mass by 3 though, because there are 3 oxygen molecules in each AgNO3 molecule).

nottim · Answer

Wait, is that all you do? I forgot.

anonymous · Answer

so 
.
107.9 + 14.01 x 16.00(3) = 169.91

nottim · Answer

you don't have to multiply the value of oxygen to the 'main body'. just multiply it by 3, then add it to the others.

anonymous · Answer

that was supposed to be an addition sign sorry

107.9 + 14.01 + 48 = 169.91

nottim · Answer

good enuff.

nottim · Answer

We clear now? You know why the oxygen molecule was multiplied by 3?

anonymous · Answer

yup

nottim · Answer

awesome. SMOKEBOMB. POOf. NOTTIM AWAYYYY