Question

consider the reaction 2 Al(s) + Fe2O3(s) = 2 Fe(l) + Al2O3(s). If 2 moles of Al(s) and 3 moles of Fe2O3(s) are avaible at the start of the reaction,

1. Which substance will be the limiting factor?
2. How many moles Al2O3(s) will be produced?

Answer 1

did you learn about stoichiometry yet?

Answer 2

yes

Answer 3

cause that stuff was hard for me. i think though that its probably in relation to that

Answer 4

exacty in relation to it. I was doing fine until I hit this part and balancing equation and molar and molecular masses and moles is all very confusing right now

Answer 5

eh, if you're still here, sorry, but I can't do much, aside fom suggesting Khan's Academy (the website), and suggestin maybe a look at examples and text from your textbook. desolée

Answer 6

I really need the help so anything I can get. I managed to get an 80 on my semester exam yay!! I tought I'd come on here and try to to learn some more and improve my skill. I'm not necessarily thrilled with an 80% but it is still way better than I thought I would do. Anyway thanks for the help on my last problem and for the recommended website :) Time for me to go to bed

Answer 7

consider the reaction 2 Al(s) + Fe2O3(s) = 2 Fe(l) + Al2O3(s). If 2 moles of Al(s) and 3 moles of Fe2O3(s) are avaible at the start of the reaction,

1. Which substance will be the limiting factor?

2 moles of Al reacts with 1 mole Fe2O3(s) (from the equation), but we have 2 moles of Al and 3 moles of Fe2O3; which substance do we have too much of? 2 moles of Al can only react with 1 mole Fe2O3...

2. How many moles Al2O3(s) will be produced?

2 Al(s) + Fe2O3(s) = 2 Fe(l) + Al2O3(s)
you can see that 2 moles of Al produces 1 mole of Al2O3(s) from the equation.

Answer 8

For 1, the limiting factor will be the substance that is used up first.