Question

Select all that apply.

Solve for x, 0 <_ x <_ 2(pi)

2sinx - sqrt(3) = 0

___ (pi)/3
___(2pi)/3
___(4pi)/3
___(5pi)/3

** <_ means less than or equal to.


I kind of need step by step because I really don't know what I'm doing here.. I also have more if someone is willing to continue to help me :) Thanks so much!

Answer 1

start with
\[2\sin(x)=\sqrt{3}\] then go to
\[\sin(x)=\frac{\sqrt{3}}{2}\]

Answer 2

now you have to look for angles that lie within the range given to you that satisfy this equation

Answer 3

then find the angle (number) whose sine is \(\frac{\sqrt{3}}{2}\) which you can either memorize, or look at the unit circle on the last page of the attached cheat sheet.

Answer 4

the the first coordinate on the unit circle is cosine, the second coordinate is sine
find the corresponding angle.
you should see that one of them is \(x=\frac{\pi}{3}\)

Answer 5

Oh okay! That was a lot easier than I had imagined.. I see now, thank you :) I really appreciate it.

Answer 6

there is another one also, which you should be able to see from the cheat sheet

Answer 7

yw

Answer 8

The other is 2pi/3 :)

Answer 9

@satellite73 I have a quick question.. If I have to sqrt something, like 1/4. I would get (+/-1)/(+/-2) Right? Well should I take 1/2 & -1/2 and find the corresponding angle? If not, how do I know if I take the negative or positive?