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Please, I desperately need help with logarithms question D: Refer to image. Please help with just part a) at least. I will use the method you teach to do the other parts myself.
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You can rewrite the equation log 25 - log 3a = log5^2-log3a From given information log 3=0.477 a=3^0.477 Try it from here
I'm not sure how to continue...
(a) \[\frac{\log_{a} 25}{\log_{a} 3a}=\frac{2\log_{a} 5}{\log_{a} 3+\log_{a} a}\] \[\log_{a} a=1\] Now you just need to substitute the given values into the right hand side of the first equation above to find the answer. Can you do that?
\[\frac{2\times 0.699}{0.477+1}=You\ can\ calculate\]
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