Question

How do you simplify an trigonometric equation like the following?

Answer 1

u need ur identities, from s\[\sin^2+\cos ^2=1\] make sin the subject of the formula

Answer 2

\[\frac{ \sin ^2\theta }{ 1-\cos \theta }
=\frac{ 1-\cos ^2\theta }{ 1-\cos \theta }
=\frac{( 1-\cos \theta)(1+\cos \theta) }{ (1-\cos \theta) }\]

Answer 3

How do you get sin theta squared is equal to (1-cos)(1+cos)?

Answer 4

do u know this identity?\[\sin ^2\theta+\cos ^2\theta=1\]

Answer 5

yes.

Answer 6

now try make sin^2 the subvject of the formula what do u get?

Answer 7

u'll get a difference of two squares which i'm sure u can solve

Answer 8

you would get sin^2 theta= 1-cos^2 theta?

Answer 9

yes
can u now see that 1- cos^2 theta is a fifference of two squares?

Answer 10

1-cos^2=(1-cos)(1+cos)