Question

what volume of .337 M KOH provides enough solute to combine with the sulphuric acid in 18.6 mL of .156 M H2SO4? the reaction is

2 KOH+H2SO4=K2SO4+2H2O

plz show in detail how to do it in full easy steps ;)

Answer 1

find how many moles of acid you have, remember that it's a diprotic acid (two acidic H+'s)

M=n/L solution

and then using the balanced equation find how much many moles of KOH you need.

From there find the volume, knowing that M=n/L of solution