Closed.
first use logarithm so you get this (3/4) Log(-2)= Log (8)
sorry i messed up haha!!! dont do that.
Ok
When I used mathway it calculated x = 18, but I don't know how to get to that answer.
\[(x-2)^\frac{ 3 }{ 4 }=8\]
First you take the logarithm of both sides \[\log_{10}(x - 2)^{3/4}=\log_{10}(8) \]Using the rules of logarithms this becomes \[3/4*\log_{10}(x - 2)=\log_{10}(8) \]Multiply both sides by 4/3. This gives\[\log_{10}(x - 2)=(4\log_{10}(8))/3 \]Exponentiate both sides using base 10\[10^{\log_{10}(x -2)}=10^{(4\log_{10}(8))/3}\]Using the rules of logarithms on the left side and the rules of exponents on the right side gives\[x - 2 = (10^{\log_{10}(8)})^{4/3}\]Using rules of logarithms again on the right side gives\[x - 2 = 8^{4/3}\]\[8^{4/3}\]is just plain old 16 so\[x - 2 = 16\]\[x = 18\]
Thank you so much :D
No problem :D
Power 4/3 both sides: -> x - 2 = 2⁴ => x = 16 + 2 = 18
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