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A function f is continuous on the closed interval [5,12] and differentiable on the open interval (5,12) and f has the given values: f(5 = 10, f(6) = 7, f(9) = 11. f(12) = 8. Using these values, what is the rigjht Riemann Sum of integral 5 to 12 f(x)dx?
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\[\int\limits_{5}^{12} f(x)dx\]
oh whoops and f(11) = 12
@AtiFS @Kainui @satellite73 ?
whoops didn't mean to close the question. i thought i had it but my answer's wrong;
Is that supposed to be f(7)=6?
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lemme try again. f(5) = 10, f(6) = 7, f(9) = 11, f(11) = 12, and f(12) = 8
the graph i drew.
So the right riemann sum is basically just adding up all the rectangles of a function using the right hand side of an interval to approximate it like this kinda: |dw:1355973532448:dw|
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