i need help guys. i need 1 more solution
\[\tan(\theta)^{2}-7\tan(\theta)-12=0\]
i use the quadratic formula and i have 3 out of 4 answers. thisis my answer theta = 83.23,305.07 and 263.23. (there are in degrees) that all i got. what the 4th solution?
when u got 83.23, you add 180 to get 263.23 when u get 305.07, you subtract 180 to get 305.07-180 =... ? because, the tan is periodic with 180 degrees, that is the value of tan repeats after every 180 degrees.
omg i forgot about that. thanks a lot man. i know how to do this, is that i really forgot. thanks for refreshing my memory
welcome ^_^
wait a sec. if i subtract 180, i wil end upin the 3rd quadrant and the 3rd quadrant is sin.
' 3rd quadrant is sin.' what does that mean ?
All the quadrants are sine... and cosine.
becuase tan can only be in the 3rd and the 1st. what i meant to say is that 120 degrees is at the 2nd quad. how is tan is postive?
you got 2 roots, right ? one positive ---> 1st and 3rd Quad one negative --->2nd and 4th quad.
i dont get it.
ok, what 2 roots do u have for quadratic equation ?
for positive root, u get 83 and 263 --->1st and 3rd Quad
ok
for negative root , u get 120 and 305 approx ---> 2nd and 4th quad
125 and 305
ok i will post another question similiar to this
sure.
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