How D.L.Hospital Rules Applies
If your numerator and denominator is in the form : 0/0 or infinity/infinity, then Take the derivative for first time to see whether you are getting rid of 0/0 or infinity/infinity form..
For example: \[\lim_{x \rightarrow 0} (\frac{\tan(x)}{x})\]
So here you are getting, 0/0 form when you put x = 0 here : So: apply here L hospital rule..
plz explain me inn detial with example
I have given you example above.. Can you tell me what do you get there when you will directly put x = 0 there??
we got 0 up and down
Yep.. so to avoid this condition we will use L hospital Rule.. Okay??
Now take the derivative on up and down side with respect to x.. Can you do it, say yes or no directly..
thats why we take derivative up and down
tell me what is the derivative of tan(x) ??
1/cotx
Yes, this is the reason we are taking derivative up and down.. In case you get infinity/infinity, then also you will take derivative.. Okay??
ok
Dude, this is the other form of tan(x).. I said to tell the derivative of tan(x).. Have you studied derivatives or differentiation yet??
yes
Anyways, \[\frac{d}{dx} \tan(x) = \sec^2(x)\]
ohhh yes yes
And tell me what is the derivative of x??
1
Yep.. So finally tell me now what is your limit has become after taking derivative??
\[\lim_{x \rightarrow 0} \frac{\sec^2(x)}{1}\] Right ??
yes
And now put x = 0 here and tell me what did you get ??
\[\sec^2(0) = ??\]
we get 0
How ?
Do you know the value of : \[\sec(0)\]
sorry we get 1 and divide by 1 so we get 1 ans
Yep... So it is solved by using L hospital Rule.. Clear??
i mix sec with sin hahahaha
Ha ha ha... Be careful next time..
yep but its difficult to solve long and lenthy questions
where you from r u a teacher ?
I am just a student like you. Not a teacher..
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