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OpenStudy (anonymous):

How D.L.Hospital Rules Applies

OpenStudy (anonymous):

If your numerator and denominator is in the form : 0/0 or infinity/infinity, then Take the derivative for first time to see whether you are getting rid of 0/0 or infinity/infinity form..

OpenStudy (anonymous):

For example: \[\lim_{x \rightarrow 0} (\frac{\tan(x)}{x})\]

OpenStudy (anonymous):

So here you are getting, 0/0 form when you put x = 0 here : So: apply here L hospital rule..

OpenStudy (anonymous):

plz explain me inn detial with example

OpenStudy (anonymous):

I have given you example above.. Can you tell me what do you get there when you will directly put x = 0 there??

OpenStudy (anonymous):

we got 0 up and down

OpenStudy (anonymous):

Yep.. so to avoid this condition we will use L hospital Rule.. Okay??

OpenStudy (anonymous):

Now take the derivative on up and down side with respect to x.. Can you do it, say yes or no directly..

OpenStudy (anonymous):

thats why we take derivative up and down

OpenStudy (anonymous):

tell me what is the derivative of tan(x) ??

OpenStudy (anonymous):

1/cotx

OpenStudy (anonymous):

Yes, this is the reason we are taking derivative up and down.. In case you get infinity/infinity, then also you will take derivative.. Okay??

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Dude, this is the other form of tan(x).. I said to tell the derivative of tan(x).. Have you studied derivatives or differentiation yet??

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Anyways, \[\frac{d}{dx} \tan(x) = \sec^2(x)\]

OpenStudy (anonymous):

ohhh yes yes

OpenStudy (anonymous):

And tell me what is the derivative of x??

OpenStudy (anonymous):

1

OpenStudy (anonymous):

Yep.. So finally tell me now what is your limit has become after taking derivative??

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0} \frac{\sec^2(x)}{1}\] Right ??

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

And now put x = 0 here and tell me what did you get ??

OpenStudy (anonymous):

\[\sec^2(0) = ??\]

OpenStudy (anonymous):

we get 0

OpenStudy (anonymous):

How ?

OpenStudy (anonymous):

Do you know the value of : \[\sec(0)\]

OpenStudy (anonymous):

sorry we get 1 and divide by 1 so we get 1 ans

OpenStudy (anonymous):

Yep... So it is solved by using L hospital Rule.. Clear??

OpenStudy (anonymous):

i mix sec with sin hahahaha

OpenStudy (anonymous):

Ha ha ha... Be careful next time..

OpenStudy (anonymous):

yep but its difficult to solve long and lenthy questions

OpenStudy (anonymous):

where you from r u a teacher ?

OpenStudy (anonymous):

I am just a student like you. Not a teacher..

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