Question

Find all the zeroes of the equation.
x^3 – x^2 = –3x – 3

Answer 1

you sure about the Q ?
because that has 2 imaginary root, and one irrational root..

Answer 2

*2 complex roots

Answer 3

yes I'm sure about the question. I seriously don't know what i'm doing or where to begin

Answer 4

then that makes 2 of us...

Answer 5

I think there's a mistake in the equation.

Answer 6

What type of class is it? If it's fairly general maths, then they're not going to ask you to find a root that is actually irrational. To do that you'd need to use an algorithm to approximate it, or something like that. And it doesn't sound like that's what you'd be doing.

Answer 7

i so wanted that to be +3 instead of -3

Answer 8

The question should be :

x^3 – x^2 = –3x + 3

Answer 9

Do you have options ?

Answer 10

I'm in algebra 2. and I copied the equation from my homework so there is no mistake

Answer 11

@Jadelynn

Show me the options please.

Answer 12

the right hand side could also be 3x - 3.

And your lecturer might have written it incorrectly. So that's where the mistake is.

Answer 13

@Jadelynn

Options ?

Answer 14

hold on Imma find a way to show the options

Answer 15

These are the options :

A.i√3, –i√3, –1
B.i√3, –i √3, 1
C.√3, –√3, –1
D.i√3, 1


Right ?

Answer 16

aah, so u have options!
that simplifies it.

Answer 17

@hba How'd you do that? and yea those are the options

Answer 18

If the equation is x^3 - x^2 = -3x - 3 then none of your options are appropriate.

Answer 19

because we have seen this question earlier

Answer 20

Yeah lol and every time the post the wrong question.

Answer 21

yes, every damn time....must be printing mistake...

Answer 22

and correct Question is x^3 – x^2 = –3x + 3

Answer 23

and correct answer is ...

Answer 24

The question is

x^3 – x^2 = –3x + 3


Now rewrite this equation as

x^3-x^2+3x-3=0

Answer 25

okay?

Answer 26

Now

Consider one of the roots to be 1 or -1 and then use polynomial division.

and find the other roots.

Answer 27

or, u can factor

Answer 28

(x^3-x^2)+3x-3=0

x^2(x-1) + 3(x-1) = 0

(x-1) (x^2+3) =0

Answer 29

nw

x - 1 = 0

x = 1


or

x^2+3 =0

x^2 = -3

x = sqrt(-3) =3i

Answer 30

*really confused*

Answer 31

\[x^3 - x^2 = -3x + 3 \] factor both sides, to get:
\[x^2(x-1) = -3(x-1) \] move right hand side over to the left:
\[x^2(x-1) + 3(x-1) = 0 \] there's a common factor of x-1, so:
\[(x^2+3)(x-1) = 0\]

Answer 32

@Jadelynn

Did you understand the factoring part ?

Answer 33

a little bit

Answer 34

@Jadelynn

Do you want an explanation on how to factorize ?

Or should i continue ?

Answer 35

um you can continue

Answer 36

Now solve this.

Answer 37

@Jadelynn

Solve for x

Answer 38

So what did you get ?

Answer 39

is it C?

Answer 40

No,

What answers did you get ?

Answer 41

Do you know the complex root is

\[\sqrt{-1}=i\]

Answer 42

@Jadelynn

?

Answer 43

@hba kinda

Answer 44

So one of them is

x=1

and

\[x^2=-3\]

\[x=\sqrt{-3}\]

\[x=\sqrt{3}*\sqrt{-1},x=\sqrt{3}i \ or \ -\sqrt{3}i \]

Answer 45

sorry my computer is severely lagging but thanks for helping

Answer 46

No problem but you need to learn complex roots and factorizing

Do you want me to teach you some questions ?