here \[T _{\frac{ 1 }{ 2 }}=\] half life of radioactive material
OpenStudy (shamim):
now u can try to solve it urself
OpenStudy (anonymous):
Thanks Prof Shamin. I have my answer already
OpenStudy (anonymous):
A little easier approach for this problem is to realize that with a half-life of 30 days 90 days represent 3 half-lives of decay. you have 1/2 of 1/2 of 1/2 left ie 1/8 of the original amount is left meaning 1-1/8 =7/8 would have decayed
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