A radioactive source has a half life of 30 days. During a period of 90 days, the fraction of atoms that would have decayed would be what
so u wanna know the amount of atoms will b decayed. is not it
the formula is\[N=N _{o} e ^{ -\lambda t}\]
here N= number of atoms remaining after 90 days t= 90 days
\[N _{o}=\] total number of atoms
\[\lambda =\] decay constant
\[\lambda =\frac{ 0.693 }{ T _{\frac{ 1 }{ 2 }} }\]
here \[T _{\frac{ 1 }{ 2 }}=\] half life of radioactive material
now u can try to solve it urself
Thanks Prof Shamin. I have my answer already
A little easier approach for this problem is to realize that with a half-life of 30 days 90 days represent 3 half-lives of decay. you have 1/2 of 1/2 of 1/2 left ie 1/8 of the original amount is left meaning 1-1/8 =7/8 would have decayed
Nice one gleem
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