Question

integrate

Answer 1

ohh

Answer 2

ya

Answer 3

i wanted use u subsitution

Answer 4

This requires u substitution. Do you know it?

Answer 5

u=sinx ok then \[\frac{ du }{ -cosu }=dx\]

Answer 6

change sin^2x = 1/2-(cos2x)/2 . then integrate .

Answer 7

Nope, you want \(u\) to be an inner function. In this case the inner function is \(2x\).

Answer 8

\[u = 2x\quad du = 2dx\implies dx=du/2\]

Answer 9

\[\int\limits_{}^{} \sin^2x dx\]

Answer 10

in this inner function is sin x

Answer 11

oh

Answer 12

not 2x

Answer 13

why to choose tougher one use identities.

Answer 14

ah I see, well then the problem might require using a trigonometric identity, like the half angle formula.

Answer 15

well why can't i use u as sinx