How to find the value of infinite series? Can someone help me please
i hope theres ore specifics coming :)
\[\sum_{k=1}^{\infty}\frac{ 1 }{ 24 }(\frac{ 5 }{ 6 })^{k-1}\]
sorry I forgot to post the equation
split out the constants
how do I do that? is that the two fractions?
youve essentially got: \[\sum kc^{n-1}\] \[k\sum c^{n-1}\] \[k\sum c^{n}c^{-1}\] \[kc^{-1}\sum c^{n}\]
split out the constant and then it becomes a simple geometric series
okay so will the number I plug into be k and the fraction be c?
k and c are just generics i pulled out of thin air to fill in the places
other than that, its your exact setup
say; k=1/24 and c=5/6
okay I want to try it really quick
do you remember the formula for an infinte geometric series?
thats when you plug in numbers right?
um, there is a general formula for geometric series that would be used to finish the summation
|dw:1356047859750:dw| this one?
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