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Mathematics 16 Online
OpenStudy (anonymous):

How to find the value of infinite series? Can someone help me please

OpenStudy (amistre64):

i hope theres ore specifics coming :)

OpenStudy (anonymous):

\[\sum_{k=1}^{\infty}\frac{ 1 }{ 24 }(\frac{ 5 }{ 6 })^{k-1}\]

OpenStudy (anonymous):

sorry I forgot to post the equation

OpenStudy (amistre64):

split out the constants

OpenStudy (anonymous):

how do I do that? is that the two fractions?

OpenStudy (amistre64):

youve essentially got: \[\sum kc^{n-1}\] \[k\sum c^{n-1}\] \[k\sum c^{n}c^{-1}\] \[kc^{-1}\sum c^{n}\]

OpenStudy (amistre64):

split out the constant and then it becomes a simple geometric series

OpenStudy (anonymous):

okay so will the number I plug into be k and the fraction be c?

OpenStudy (amistre64):

k and c are just generics i pulled out of thin air to fill in the places

OpenStudy (amistre64):

other than that, its your exact setup

OpenStudy (amistre64):

say; k=1/24 and c=5/6

OpenStudy (anonymous):

okay I want to try it really quick

OpenStudy (amistre64):

do you remember the formula for an infinte geometric series?

OpenStudy (anonymous):

thats when you plug in numbers right?

OpenStudy (amistre64):

um, there is a general formula for geometric series that would be used to finish the summation

OpenStudy (anonymous):

|dw:1356047859750:dw| this one?

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