A small spaceship whose mass is 1.5x10^3 kg (include-ing an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a 10 kW laser beam, what speed will the ship attain in 1.0 day because of the momentum carried away by the beam?
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OpenStudy (shamim):
can u tell me the result option
OpenStudy (anonymous):
The answer is 1.9 mm/s.
OpenStudy (shamim):
ok
OpenStudy (shamim):
i m trying
OpenStudy (shamim):
i got the result velocity is 759 m/s
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OpenStudy (shamim):
should i explain my procedure
OpenStudy (anonymous):
Yes, show me the work you did.
OpenStudy (shamim):
ok i m showing
OpenStudy (shamim):
let
m= mass
p=power
t=time
F=force
s= distance
OpenStudy (shamim):
v=final velocity
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OpenStudy (shamim):
a= acceleration
OpenStudy (shamim):
Now\[P=\frac{ W }{ t }=\frac{ Fs }{ t }=F\frac{ s }{ t }=Fv\]
OpenStudy (anonymous):
What is the distance, s?
OpenStudy (shamim):
\[or, 10000=Fv \]
OpenStudy (shamim):
we know work= force* displacement or distaance
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OpenStudy (shamim):
or, \[F=10000/v\]
OpenStudy (shamim):
now we know \[F=ma\]
OpenStudy (shamim):
or, \[F=1500a\]
OpenStudy (shamim):
or, \[10000/v=1500a\]
OpenStudy (shamim):
r u getting my work
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OpenStudy (shamim):
or, \[a=10000/1500v\]
OpenStudy (shamim):
now another law of motion is \[v=u+at=0+at=at=(10000/1500v) \times 24 \times 60 \times 60\]
OpenStudy (shamim):
now solve it for v
OpenStudy (anonymous):
Never mind. I found a formula for this problem, but thanks for the help.