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Physics 12 Online
OpenStudy (anonymous):

A small spaceship whose mass is 1.5x10^3 kg (include-ing an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a 10 kW laser beam, what speed will the ship attain in 1.0 day because of the momentum carried away by the beam?

OpenStudy (shamim):

can u tell me the result option

OpenStudy (anonymous):

The answer is 1.9 mm/s.

OpenStudy (shamim):

ok

OpenStudy (shamim):

i m trying

OpenStudy (shamim):

i got the result velocity is 759 m/s

OpenStudy (shamim):

should i explain my procedure

OpenStudy (anonymous):

Yes, show me the work you did.

OpenStudy (shamim):

ok i m showing

OpenStudy (shamim):

let m= mass p=power t=time F=force s= distance

OpenStudy (shamim):

v=final velocity

OpenStudy (shamim):

a= acceleration

OpenStudy (shamim):

Now\[P=\frac{ W }{ t }=\frac{ Fs }{ t }=F\frac{ s }{ t }=Fv\]

OpenStudy (anonymous):

What is the distance, s?

OpenStudy (shamim):

\[or, 10000=Fv \]

OpenStudy (shamim):

we know work= force* displacement or distaance

OpenStudy (shamim):

or, \[F=10000/v\]

OpenStudy (shamim):

now we know \[F=ma\]

OpenStudy (shamim):

or, \[F=1500a\]

OpenStudy (shamim):

or, \[10000/v=1500a\]

OpenStudy (shamim):

r u getting my work

OpenStudy (shamim):

or, \[a=10000/1500v\]

OpenStudy (shamim):

now another law of motion is \[v=u+at=0+at=at=(10000/1500v) \times 24 \times 60 \times 60\]

OpenStudy (shamim):

now solve it for v

OpenStudy (anonymous):

Never mind. I found a formula for this problem, but thanks for the help.

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