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Mathematics 15 Online
OpenStudy (anonymous):

|x^2+2x|≤x

OpenStudy (anonymous):

you can open up the modulus and get -x<x^2+2x<x

OpenStudy (anonymous):

how do you solve though. i cant do it..

OpenStudy (zarkon):

notice that x needs to be non-negative

OpenStudy (zarkon):

and that \(2x>x\) for \(x>0\) and thus \(x^2+2x>x\) for all \(x>0\)

OpenStudy (zarkon):

therefore the only solution is...

OpenStudy (anonymous):

is there a way to do this algebraically?

OpenStudy (zarkon):

x<0 is not in the solution set

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