Question

Solve the compound inequality.
5x + 11 ≥ –9 and 10x – 3 ≤ 27

A. x ≥ –4 and x ≤ 3
B. x ≥ –4 and x ≤ 2 2/5
C. x ≥ 2/5 or x ≤ 2 2/5
D. x ≥ 2/5 or x ≤ 3

Answer 1

for 5x+11 >= -9
subtract 11 on both sides..
then divide both sides by 11
what will you get?

Answer 2

5x > -20

Answer 3

He meant divide both sides by 5 to find x.

Answer 4

ah that makes more sense

Answer 5

x > -4

Answer 6

Yes.
Then solve for x in the other expression: 10x-3 <=27

Answer 7

Add 3 to both sides.
The divide both sides by 10 to find x.

Answer 8

x ≤ 3

Answer 9

Yes ans.:
x>=-4 and x<=3. The 'and' comes from the 'and' in the original question.

Answer 10

So that would be A.

Answer 11

Got any questions?

Answer 12

thanks. Do you think you could help me on another question?

Answer 13

Sure.

Answer 14

Solve the absolute value equation.
│3x + 1│ = 1

Answer 15

1. To solve an absolute value equality question the absolute expression needs to be by itself on one side:
|3x+1| = 1. So we have that.
2. The absolute value of an expression is always greater than or equal to zero. If the number on the right is negative then there is "NO SOLUTION". In this case there is a solution because we have a positive '1'.
3. We have 2 cases:
3x+1 = 1 or 3x+1=-1
Then solve for x in both cases.

Answer 16

i know from the options its either B or D.
B. x = -2/3 or x = 0
D. x = 1 or x = 0

Answer 17

3x+1 = 1 or 3x+1=-1
Solve for x in both equations above, what do you get?

Answer 18

B. x = -2/3 or x = 0

Answer 19

Good deal, any questions about how i got this?

Answer 20

Nope. You've explained pretty well

Answer 21

Do you have anymore questions you would like to ask?

Answer 22

probably but not at the moment

Answer 23

@philo1234 How do you figure out sloe intercepts?

Answer 24

x-intercept is where the graph crosses the x-axis at this point y =0 (always).
y-intercept is where the graph crosses the y-axis, at this point x=0 (always).
Eg.: y = x + 2.
The x-int is x+2=0. That is x=-2.
The y-int is y=0+2. That is y=2

Answer 25

so for –6x + 3y = 12. it would be:
-6x + 3(0) = 12. -6x = 12. x = -2.
-6(0) + 3y = 12. 3y = 12. y = 4.

Answer 26

Yes that's correct

Answer 27

Yay =^..^=

Answer 28

how do I figure out the equation based on the slope?

Answer 29

The questions come in 2 forms:
1. Give you 2 points on a line:
a. Find the slope using the 2 points.
b. Use the point slope form: y-y1=m(x-x1), where x1 and y1 is the x and y value of one of the points and m is the slope.
2. Give you the slope and a point:
a. Use the point slope form: y-y1=m(x-x1), where x1 and y1 is the x and y value of the point given and m is the slope..

Answer 30

the problem only gives me
point: (9, 3); slope: 4/9

Answer 31

Eg1. Find the equation of the line given the point (3,0) and (1,4).
Slope (m) = -2
Choose one of the points: (3,0) - x1 = 3 and y1=0
Point-slope form: y-0=-2(x-3)
Answer in slope intercept form: y=-2x+6
Answer in standard form (ax+by=c) = 2x+y=6

Eg2. Find the equation of the line given the slope -2 and the point (1,4)
m=-2, x1=1, y1=4.
Point-slope form: y-4=-2(x-1)
Answer in slope intercept form: y=-2x+6
Answer in standard form (ax+by=c) = 2x+y=6

Answer 32

So your question is similar to Eg2 use the same approach to find the equation. Can you do that?

Answer 33

I can try

Answer 34

y - 9 = 4/9(x-3)

Answer 35

nope: y-3=4/9(x-9), remember point-slope form: y-y1=m(x-x1). Should your answer be in a specific form?

Answer 36

that is the form it wants

Answer 37

So answer would be: y-3=4/9(x-9), Note that the 3 is the y-value and 9 is the x-value taken from the point given.