Question

V0=5V, T=0.5ms, Rw=3Ω, Lw=1mH and RL=2Ω for part 1 and 2 i got 0.2 each.kindly help with part 3 and 4.last check remaining

Answer 1

Final MIT 6.002x Solution

Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm
b)iA =(-i2)*R/(2*R+rm) and V0=ia*rm
c) part a) + part b)
d)2R

Q2 p1: Vs as vin<vt
p2: v0 = vs-kr(e^((vin-vt)/vn)-1)
p3: vin = ln(vs/2kr +1)vn+vt
p4: vin=sqrt(vs/kr)+vt
p5: -kre^((vin-vt)/vn)
p6: -kr(vin-vt)

Q3 same as HP8p1

Q4 p1=V*R2/(R1+R2)*(1-e^(-(R1+R2)*t/(R1*R2*C)))
p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(t-T))
p3=C*(V*R2/(R1+R2))*sin((t-T)*1/sqrt(L*C))/sqrt(L*C)

Q5
E
V
B
Y
F
Z

Q6
1) Time constant is L/Rtotal -> 1/5=0.2
2) Time constant is L/Rtotal -> 1/5=0.2
3) Vmax is 5.95840 V
4) Vmin is 0.040 V