Question

The circuit parameters have the following values: VS=4.5V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V.

Given that vIN=0.5V, what is the value of vOUT in Volts?

unanswered
Given that vIN=2V, what is the value of vOUT in Volts?

unanswered
What is the value of vIN in Volts when vOUT drops to VS2?

unanswered
Now you replace the ExpFET with a MOSFET with parameters K=1mAV2, and VT=1V.

Assuming the MOSFET is operating in the saturation region, what is the value of vIN in volts when vOUT drops to VS2? (Recall that for a MOSFET in saturation: iD=K2(VGS−VT)2

Answer 1

You'll find the formulas here: http://openstudy.com/study#/updates/50d36174e4b0b19ec2190832

Answer 2

i want answers

Answer 3

please anyone

Answer 4

Nobody is going to give you answers. If you can't even put values in a formula, then there's no point in passing this exam.

Answer 5

just shetup and getlost

Answer 6

Haha, lost your brain?

Answer 7

the pronlem1 formula of q2 i cant understand

Answer 8

sry rmpk

Answer 9

K,UTCFGRJYMB,Y

Answer 10

@rva.raghav
1. 4.5
2. 2.7818
3. 2.1786
4. 3.1213
5. -2.7182
6. -1

Answer 11

@rva.raghav

if correct please click best response.

Answer 12

Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm
b)iA =(-i2)*R/(2*R+rm) and V0=ia*rm
c) part a) + part b)
d)2R

Q2 p1: Vs as vin<vt
p2: v0 = vs-kr(e^((vin-vt)/vn)-1)
p3: vin = ln(vs/2kr +1)vn+vt
p4: vin=sqrt(vs/kr)+vt
p5: -kre^((vin-vt)/vn)
p6: -kr(vin-vt)

Q3 same as HP8p1

Q4 p1=V*R2/(R1+R2)*(1-e^(-(R1+R2)*t/(R1*R2*C)))
p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(t-T))
p3=C*(V*R2/(R1+R2))*sin((t-T)*1/sqrt(L*C))/sqrt(L*C)

Q5 E
V
B
Y
F
Z

Answer 13

@rishikesh.147 If you're so smart, give the formula for Q6. Wait, you can't, cause all you do is copy other's formulas, trying to get credit for them. Haha, you're so lame!