Question

A cone and a square- based pyramid have slant heights of 6 in. The diameter for the cone and the base edge of the pyramid are both 8 in.

a. Which space figure has thye greater surface area?

b. By how much does the greater surface area exceed the lesser? Use 3.14 for ╥

Answer 1

someone please help me

Answer 2

a. Figure out the surface areas of both figures. To calculate the cone, use SA = (Pi)rs + (Pi)r^2. Remember that r=1/2d, so r = (1/2)8 = 4. Plug everything in:
SA(cone) = (pi)(4)(6) + (pi)(4)^2
SA(cone) = 75.4+50.27
SA(cone) = 125.67
For the square, use the formula SA = 2bs + b^2
SA(square) = 2(8)(6) + (8)^2
SA(square) = 96 + 64
SA(square) = 160
The square has a bigger surface area.

Answer 3

b. Using 3.14 for the cone formula, the surface area is 125.6 exactly. To find the difference, subtract 160 - 125.6, so the greater exceeds the lesser by 34.4 in^2

Answer 4

thanks a lot

Answer 5

no problem!

Answer 6

:)