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How do I find the derivative of. 180 * (.5)^x
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Rewrite it as\[f(x)=(180 ) (.5)^x=180e^{xln(.5)}\]Let u=x ln(.5) and use the chain rule.
So\[f'(x)=180 \ln(.5) e^{x \ln(.5)}=180 \ln(.5) (.5)^x\]
Hope that was helpful.
Thank you. I thought if I could do it with the rule of \[b^x = \ln(b)*b^x\] but the 180 threw me off.
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