Question

i really need help with algebra 2

Answer 1

1. Find all the real fourth roots of . (1 point) and
4/7 and 16/49
-4/7 and 4/7
4/7,-4/7,16/49,,-16/49
4/7

Answer 2

I got -4/7 amd 4/7 which is B

Answer 3

2. What is a simpler form of the radical expression?


(1 point)36|g3|
36g4
6|g3|
6g4

Answer 4

lemme guess, the absolute value bars kinda threw you off?

Answer 5

yes

Answer 6

well just ignore them, pretend the choices are:
A.) 36g^3
B.) 36g^4
C.) 6g^3
D.) 6g^4

Answer 7

then find the square root of 36 which is?

Answer 8

6

Answer 9

good, then find x+x=6 for the exponent of the g

Answer 10

is it c

Answer 11

yepp thats right

Answer 12

The formula for the volume of a sphere is v=3/4pie r ^3. Find the radius, to the nearest hundredth, of a sphere with a volume of 15 in.3
(1 point)

Answer 13

Okay I had problems with this one too but I got it. Set it up like this:
15=4/3(3.14)r^3
ok?

Answer 14

okk

Answer 15

then to divide by a fraction, you just multiply by its reciprocal like this:
15(3/4)=3.14r^3

Answer 16

i multiply 15(3/4) together

Answer 17

yeah then you'll have 45/4 which is 11.25.
so then you have 11.25=3.14r^3

Answer 18

do i now divide 11.25 with3.14

Answer 19

yepp

Answer 20

3.11r3

Answer 21

no,11.25/3.14 should be 3.58 then 3.58=r^3 then find the cube root of 3.58 to get r.

Answer 22

i got 3

Answer 23

for the cube root of 3.58?

Answer 24

i think

Answer 25

try it again

Answer 26

i dont remember how to get the cube root

Answer 27

\[\sqrt[3]{3.58}\]

Answer 28

find x*x*x-3.58, it's a decimal. you'll get r=1.52977541 then round to get r=1.53 in.

Answer 29

10. What is the simplest form of the quotient?


(1 point)

Answer 30

\[\sqrt[3]{\frac{ 162 }{ 2 }}\]

Answer 31

is that the answer

Answer 32

7. Kepler’s Third Law of Orbital Motion states that you can approximate the period P (in Earth years) it takes a planet to complete one orbit of the sun using the function , where d is the distance (in astronomical units, AU) from the planet to the sun. How many Earth years would it take for a planet that is 6.76 AU from the sun? (1 point)15.23
17.58
154.46
3.58

Answer 33

no you have to simplify more, what is 162/2

Answer 34

81

Answer 35

good, now what is the square root of 81?

Answer 36

9

Answer 37

okay so it goes
81
/ \
9 9
/\ /\
3 3 3 3
now since your finding the cube root, you have to find 3 of the same number. are there any?

Answer 38

yes three

Answer 39

okay so move 3 to the outside of the radical like this\[3\sqrt[3]{x}\]

Answer 40

but there's 4 three's so there is one left under the radical after you move the others out in front of the radical

Answer 41

thats it

Answer 42

yeah, so whats the final answer look like
?

Answer 43

3 square root of x/3

Answer 44

close, but it would be a cube root instead of a square root. so its \[3\sqrt[3]{3}\]

Answer 45

7. Kepler’s Third Law of Orbital Motion states that you can approximate the period P (in Earth years) it takes a planet to complete one orbit of the sun using the function , where d is the distance (in astronomical units, AU) from the planet to the sun. How many Earth years would it take for a planet that is 6.76 AU from the sun? (1 point)15.23
17.58
154.46
3.58

Answer 46

please close questions that you are done with so that you may post a new question in the "ask a question" box.

Answer 47

OK