Question

7. Kepler’s Third Law of Orbital Motion states that you can approximate the period P (in Earth years) it takes a planet to complete one orbit of the sun using the function , where d is the distance (in astronomical units, AU) from the planet to the sun. How many Earth years would it take for a planet that is 6.76 AU from the sun? (1 point)15.23
17.58
154.46
3.58

Answer 1

This one was hard. \[P=6.76^{\frac{ 3 }{ 2 }}\]

Answer 2

whats 3/2?

Answer 3

1 1/2

Answer 4

good, so 1.5. now it looks like this \[P=6.76^{1.5}\]

Answer 5

YES

Answer 6

then do 6.76^1.5 and you'll get the answer

Answer 7

MULTIPLY 6.76
1.50

Answer 8

DO I MULTIPLY THEM

Answer 9

no 1.5 is the exponent

Answer 10

THEN WHAT HOW DO I GET THE ANSWER

Answer 11

i told you do \[6.76^{1.5}\]

Answer 12

3.58

Answer 13

no

Answer 14

17.58

Answer 15

yes, good job

Answer 16

5. Simplify . (1 point)
9
81


5. Simplify . (1 point)
9
81

Answer 17

9 1/3 81 1/3

Answer 18

3.d
4.b
5.a

Answer 19

no, none of those are right,

Answer 20

3. p=2l+2w
\[p= 2(7\sqrt{13})+2(\sqrt{13})\] \[p=14\sqrt{13}+2\sqrt{13}\] \[p=16\sqrt{13}\]

Answer 21

16 square root 13 so its b

Answer 22

yepp

Answer 23

i dont get # 4

Answer 24

you have to factor oout the numbers like we did with the cube root earlier but this time its only square root so you only need groups of 2 of the same number

Answer 25

like for 20 it'd be
20
/ \
5 4
/ \
2 2

Answer 26

2

Answer 27

okay so then you put the 2 outside the radical and leave the five under it so it looks like this:\[2\sqrt{5}\]

Answer 28

then do the same thing with the 45
45
/ \
5 9
/ \
3 3

Answer 29

I just finished this test, scored 100
1. B: -4/7 and 4/7
2. C: 6|g^3|
3. B: 16(sqrt)13 units
4. A: 4(sqrt)5
5. B: 9
6. C: 8x ^-15/7
7. B: 17.58
8. A: x^3/5

For the last two, I have not been graded yet so use these at your own risk
9. -3 / (7 - 2(sqrt)10)
(2 + 5) / (2 - 5) =
(2 + 5) * (sr2 - sr5) / (sr2 - sr5) * (sr2 - sr5) =
(sr2 - sr5) / (sr2 - sr5) =
(2 - 5) / (sr2 - 2sr10+sr5) =
-3 / (2 - 2(s)10 + 5) =
-3 / (7 - 2(sqrt)10)
10. a^2/4