Question

A spinner has 10 equal sections, 4 red and 6 green. Given two spins, what is the probability it lands on red at least once?

Answer 1

need help please

Answer 2

P(two G) = P(G) X P(G) = 0.6 X 0.6 = 0.36
So the probability of at least one red is 1 - 0.36 = 0.64
is this right

Answer 3

that is correct, or you can say

P(at least one red) = P(1 red, 1 green) + P(1 green, 1 red) + P(1 red, 1 red)

P(at least one red) = P(1 red)*P(1 green) + P(1 green)*P(1 red) + P(1 red)*P(1 red)

P(at least one red) = 0.4*0.6 + 0.6*0.4 + 0.4*0.4

P(at least one red) = 0.64

Answer 4

thnx so much

Answer 5

np