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Mathematics 19 Online
OpenStudy (anonymous):

You have two pieces of wood that will make up two sides of a triangular picture frame. One is 6 in. long and the other is 7 in. long. What is the range of the possible lengths for the third side of the frame? I don't remember learning about finding the range of possible lengths...

OpenStudy (perl):

you can use the triangle inequality

OpenStudy (perl):

the triangle inequality, suppose the three sides are a,b,c. the inequality theorem says the sum of any two sides must be greater than the third side

OpenStudy (perl):

, this is an inequality

OpenStudy (anonymous):

Yes, but how would I answer the question? I have several like this one but I don't get the range part. How would I use that?

OpenStudy (anonymous):

Wait, all I would have to do is make sure its less then the sum right?

OpenStudy (perl):

so if a,b,c are the three sides of a triangle we have a+ b > c a + c > b b + c > a

OpenStudy (perl):

you are given 6,7,x for the sides of your triangle, since we don't know the third side

OpenStudy (perl):

6 + 7 > x 6 + x > 7 x + 7 > 6

OpenStudy (perl):

solving this we get x > 1 , x < 13 x is between 1 and 13

OpenStudy (anonymous):

That problem was a lot harder then I thought it was. I could of done that mentally. Thank you so much!

OpenStudy (perl):

thanks, and to show your appreciate , you can click best response

OpenStudy (anonymous):

Haha, thanks

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