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Given: P(A) = 0.45, P(B) = 0.25, P(AUB) = 0.7, a) Determine P(A∩B) b) Are A and B mutually exclusive? Explain
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A) is that 0 the answer
B) it's mutally exclusive, because the two sets have no elements in common
P(AUB) =P(A) + P(B) - P(AnB)
ya
i got 0
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use it to find P(AnB)
i did
u got 0?
i got 0 the result
good
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right
if the sets are exclusive then \[(A n B) = \phi \]
Since P(AnB) =0 it is mutually exclusive event
what about B
explain in B
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Since P(AnB) =0 it is mutually exclusive event
B) it's mutally exclusive, because the two sets have no elements in common
right
yep
thnx
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they might not be mutually exclusive \[P(A\cap B)=0\] does not imply that \(A\cap B=\emptyset\)
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