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Mathematics 15 Online
OpenStudy (anonymous):

Given: P(A) = 0.45, P(B) = 0.25, P(AUB) = 0.7, a) Determine P(A∩B) b) Are A and B mutually exclusive? Explain

OpenStudy (anonymous):

A) is that 0 the answer

OpenStudy (anonymous):

B) it's mutally exclusive, because the two sets have no elements in common

OpenStudy (anonymous):

P(AUB) =P(A) + P(B) - P(AnB)

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

i got 0

OpenStudy (anonymous):

use it to find P(AnB)

OpenStudy (anonymous):

i did

OpenStudy (anonymous):

u got 0?

OpenStudy (anonymous):

i got 0 the result

OpenStudy (anonymous):

good

OpenStudy (anonymous):

right

OpenStudy (anonymous):

if the sets are exclusive then \[(A n B) = \phi \]

OpenStudy (anonymous):

Since P(AnB) =0 it is mutually exclusive event

OpenStudy (anonymous):

what about B

OpenStudy (anonymous):

explain in B

OpenStudy (anonymous):

Since P(AnB) =0 it is mutually exclusive event

OpenStudy (anonymous):

B) it's mutally exclusive, because the two sets have no elements in common

OpenStudy (anonymous):

right

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

thnx

OpenStudy (zarkon):

they might not be mutually exclusive \[P(A\cap B)=0\] does not imply that \(A\cap B=\emptyset\)

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