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Calculus1
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Trigonometry Integration HELP
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\[\int\limits_{}^{} \frac{ 1-\sin(x) }{ \cos(x) }dx\]
is ur question (1- sinx)/cosx
yes
then we know (a+b)/c =a/c +b/c
so (1- sinx)/cosx =1/cosx -sinx/cosx
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actually we r simplifying the question first
now 1/cosx =secx
and sinx/cosx =tanx
now i hope its clear to u...
HOW DID YOU INTEGRATE >>>>>> ∫(secx -tanx)dx <<<<<<<
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oops !!!!!!!!!!!! ∫secx dx =ln (secx+tanx)
so ∫(secx -tanx)dx =ln (secx+tanx) -lnsecx +c
THANK YOU VERY MUCH
@S0fw0N thanks for correcting
welcome
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THANKs @stgreen
welcome
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