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Mathematics 13 Online
OpenStudy (kainui):

If we see f(t+T)=f(t) Can we assume f((t+T)+T)=f(t)

OpenStudy (anonymous):

f((t+T)+T) = f(t+T) =f(t)

OpenStudy (anonymous):

So, I guess yes

Parth (parthkohli):

That'd be a true assertion if the first statement is true for all \(t\). We can assume \(t = t + T\) and carry on...

hartnn (hartnn):

f(t) periodic with time T so, \(f(t \pm nT)=f(t)\) also true.

OpenStudy (phi):

yes, that is the definition of a periodic function however I would not say t= t+T, only that f(t)=f(t+T)

Parth (parthkohli):

Is \(T\) not a variable?

Parth (parthkohli):

Ah, it is a periodic function indeed.

OpenStudy (phi):

presumably they mean T is a constant here...

OpenStudy (kainui):

Yes, exactly I'm just making sure this is something implied by the statement f(t+T)=f(t) thank you very much everyone! =D

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