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Mathematics 4 Online
OpenStudy (anonymous):

Why isn't the inverse of a function always a function?

OpenStudy (ghazi):

okay just suppose that you have a function lets say y= sin x now inverse of it will be \[x= \sin^{-1}y\] so does the definition of function applies in inverse, try it ?

OpenStudy (ghazi):

did you get it?

OpenStudy (anonymous):

uhm no,

OpenStudy (ghazi):

for defining a function it should have one output to the one input but when you will reverse the condition that is inverse , you will have same x for two Ys which contradicts the definition of function

OpenStudy (ghazi):

and in some cases it is possible the inverse of a function could be a function like if i say y=f(x)=x its inverse could be a function but if i say y= x^3 its a function but inverse is not a function

OpenStudy (ghazi):

still confused? @srw1496

OpenStudy (anonymous):

uh yeah...

OpenStudy (anonymous):

i am confused if \(f(x)=x^3\) then \(f^{-1}(x)=\sqrt[3]{x}\) which is a function

OpenStudy (ghazi):

@satellite73 i was missing you and i knew this

OpenStudy (ghazi):

@srw1496 look fundamentally just check out the definition of function and if the inverse of function gives two values for same input then it is not a function

OpenStudy (ghazi):

and yes my apology for choosing wrong example

OpenStudy (anonymous):

on the other hand, lets look at \(f(x)=x^2\) here we have \(f(2)=2^2=4\) and \(f(-2)=(-2)^2=4\) as well so both \((-2,4)\) and \(2,4)\) are on the graph but if you switch the ordered pairs, then you get both \((4,-2)\) and \((4,2)\) so the inverse is not a function

OpenStudy (anonymous):

the difference is \(x^3\) is a "one to one" function, which means two different inputs give two different outputs but \(x^2\) is not a one to one function, different inputs can give the same output

OpenStudy (ghazi):

y=x^2 is not a function

OpenStudy (kainui):

q is not a letter

OpenStudy (anonymous):

????!!!!

OpenStudy (kainui):

What are you talking about, seriously?

OpenStudy (kainui):

First you tell me arcsine isn't a function and now this? lol

OpenStudy (anonymous):

this is not a pipe

OpenStudy (ghazi):

yes plot y=x^2 and use straight line test , straight line cuts the parabola twice so its not a function

OpenStudy (ghazi):

lets play

OpenStudy (kainui):

|dw:1356208624058:dw|

OpenStudy (anonymous):

y=x^2 is a function. x=sqrt(y) is not for all y. Only positive y.

OpenStudy (ghazi):

|dw:1356208670981:dw| function @Kainui dad

OpenStudy (ghazi):

LOL

OpenStudy (anonymous):

uhhh i have no idea what is going on...

OpenStudy (anonymous):

It's not injective. That doesn't mean it isn't a function...

OpenStudy (ghazi):

we are having useless debate but @srw1496 i think @satellite73 has explained everything that is all you need to know

OpenStudy (kainui):

You cut yours the wrong way, kid. Study my picture carefully and you'll see.

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