Question

can i get help with this?

Answer 1

Yes.

Answer 2

Multiply the left fraction by x+3 over x+3 and the right fraction by (x+3)^2 over (x+3)^2

Answer 3

No no no, don't do that

Answer 4

Given you (2x+6)(x+3)/(x+3)^3 + x(x+3)^2/(X+3)^23

Answer 5

You only need to multiply the right side by x+3/x+3 to make the bottom halves the same

Answer 6

Make the denominators the same

Answer 7

By multiplying the right fraction by x+3 over x+3

Answer 8

\[\frac{ x(x+3) }{ (x+3)^2 }\]

Answer 9

and \[\frac{ 2x+6 }{ (x+3)^2 }\]

Answer 10

so \[\frac{ x^2 + 5x + 6 }{ (x+3)^2 }\]

Answer 11

And the top factorises into (x+3)(x+2)

Answer 12

So one of the (x+3)s on the bottom cancels with the one on the top

Answer 13

Leaving \[\frac{ (x+2) }{ (x+3) }\]