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If a line L1 has equation y=mx+b, where m and b are both constants with \[m \neq 0\], the an equation of a line L2 perpendicular to L1 has the form \[y=-\frac{ 1 }{ m }x+C\] where C is a constant.
True or False?
When lines are perpendicular to one another, the slope of one line will be the NEGATIVE RECIPROCAL of the other. If one line has slope m, Then the other line will have slope -1/m. The reason we have +C in the second line equation instead of +b is cause the line will have a different y-intercept. Does the slope they gave us match that explanation? :o
so True
Zepdrix, I honestly have no idea...lol
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it is TRUE
thank you!
cuz the 1st line has a slope of (m) the 2nd line has a slope of (-1/m)
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