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OpenStudy (anonymous):
What is the empirical formula of a compound that is 27.3% C and 72.7% O?
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OpenStudy (abb0t):
Assume 100 g of sample. 27.3% = 0.273 g of carbon 72.7% = 0.727 g of oxygen convert to moles to get an approximate estimate. your answers will be in decimal points. Divide by the smallest molar amount to get whole numbers. You should get: \[CO_2\]
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