Question

i need help with rational expressions

Answer 1

Ok, so once again the denominators are again so it can be rewritten as
\[\frac{ 2x+4-2 }{ x ^{2} -1}=\frac{ 2x+2 }{ x ^{2} -1}\]
Then you can factorise both the top and bottom to cancel parts out. In this case (x+1) can go into both.
\[\frac{ 2(x+1) }{ (x+1)(x-1)}\]
Then cancel out the (x+1)'s and you've simplified it to:
\[\frac{ 2 }{ x-1 }\]
I hope that helps!

Answer 2

The denominators are the same, not "again", sorry!