Question

What is the theoretical period with a length of a pendulum with 0.477

Answer 1

Also What is the theoretical period with a length of a pendulum with 0.3785?

Answer 2

@nubeer
@MathLegend
@mathawesomeness
@mathgeek898

Answer 3

is it 3???

Answer 4

.47 what? feet meter?

Answer 5

seconds

Answer 6

What is L & G stand for

Answer 7

L : pendulum length
g : acceleration of gravity

Answer 8

0.477 is NOT in seconds<<<<<<<<

Answer 9

what is it ??

Answer 10

minutes maybe, Im not sure.

Answer 11

is it in [CM]

Answer 12

no it is Length

Answer 13

[cm] or [in]

Answer 14

Its not inches i thought it was in time but it is cm

Answer 15

i think its in [m] did u convert in the LAB

Answer 16

no

Answer 17

im not even sure how to do the last chart im just doing wht i think is right

Answer 18

how did u come up with that? And did i get the experimental period right?

Answer 19

is it 0.47 cm ?

Answer 20

Experimental Period 0.477

Answer 21

good luck

Answer 22

what is experimatal period for 2?

Answer 23

@julliemyers Listen to your self, it's likely you say that your height is .....second!!!

Answer 24

the awsners i had for length pendulum are the same as the experimatal perod?

Answer 25

\[T = 2 \pi \sqrt{\frac{ L }{ g }}\]

T is period, L is length, g is gravity (9.8m/s^2). This is valid as long as the angle you swing it at isn't too steep.

Answer 26

T is in seconds, L in metres.

Answer 27

the angle was 20 degress

Answer 28

20 degrees should be fine for that formula. But what are those lengths 0.477 and 0.3785...? You need units. Below that you have the length as 25.6cm and 12.7cm, so what are 0.477 and 0.3785 supposed to be?

Answer 29

20 degrees to the vertical, that is. Like this:

Answer 30

Don't put your times in minutes - use seconds. Things like the average time for 10 swings and period of pendulum should be in seconds.

Answer 31

If you're using gravity as 980cm/s^2, then it's okay to use length L in cm.

Answer 32

Experimental Period 0.477 is a time its not a Length

Answer 33

But it's listed in the table under Length of Pendulum...

Answer 34

but if you chk the work its Time NOT length

Answer 35

its the sum of the " Period of pendulum "

Answer 36

Yeah, that's what I figured, i was about to enter her numbers into the formula. If she's used minutes for the period t, then it's not correct, since gravity is in seconds.

Answer 37

yeah

Answer 38

you can use this site http://tini.cc/f6z to eaz your calculations

Answer 39

Ah, yes hyperphysics is handy that way.

Answer 40

@julliemyers first convert your times in minutes into seconds. Then use the formula for period (in seconds), using your length (in cm):

\[T = 2 \pi \sqrt{\frac{ L }{ 980}}\]

Answer 41

There'll be several reasons why your experimental times are off from the theoretical times - friction, air resistance, human error (in timing etc). The formula for period is also simplified - it assumes the string has no mass, which of course isn't true in a real pendulum.

If the mass of the bob is much heavier than the mass of the string, your experimental times will be more accurate.

Answer 42

Well, let me know if you need any more help/clarification.

Answer 43

Idk if you still need help on this, but your "Experimental Period" in the last table, should be the same as the "period of pendulum" from your other two tables. Experimental period just means what period you got from your experiment's results. Convert all the minutes into seconds.

The "length of pendulum" is the length of the string you used, which looks like 25.6cm.

Theoretical period is what you get from the formula, by using the length 25.6cm, and the period will be in seconds.

Answer 44

thanks but i alredy turned it iin

Answer 45

@julliemyers what was your answers for this or how did you get it

Answer 46

@agent0smith do you know what it is or are you just looking

Answer 47

^if you read through it you'll see I answered it already.

Answer 48

oh sorry lol