Question

I'm having some trouble on this question, can someone please help, and show the steps?

Find 2 numbers whose sum is 17 and whose product is 72.

Answer 1

can u factor 72 ?

Answer 2

What do you mean factor 72? I got up to this step.

x+y=17
x*y=72
x=17-y y=17-x

(17*y)xy=72
17y-y^2=72 <-------- I'M STUCK ON THIS BIT!!

Answer 3

alternate way :
use
\(\large (x-y)^2 = (x+y)^2-4xy\)
to get x-y,
then you have x+y and x-y also, which is easily simultaneously solvable.

Answer 4

x+y=17
x+(17-x)


x(17-x)=72


-x^(2)+17x-72=0


x^(2)-17x+72=0

(x-8)(x-9)=0


x=8,9

Answer 5

Can you please help from the start?

Answer 6

sure,
you have x+y and xy, right ?
you can find x-y from the identity i have given,
what u get as x-y from that ?

Answer 7

let one number be x and the other be y

ex. 4+2=6 === 4+(6-4)=6

Answer 8

\((x-y)^2 = 17^2-4(72)=...?\)

Answer 9

then take it from there.:)

Answer 10

@hartnn you Blow my Mind

Answer 11

how exactly ?

Answer 12

ohh..literally...

Answer 13

you r the BEST bro