Question

can't find the inverse even though tried 2-3 times. Can anybody help??

Answer 1

The Matrix is

4 -1 1
2 2 3
5 -2 6

Answer 2

There is a trick to finding matrix of 3x3.

Answer 3

1) Find the determinate of the matrix.

Answer 4

Can u show me??

Answer 5

I have to solve this by adjoining it to an identity matrix

Answer 6

2) The inverse = \[\frac{ 1 }{ \det(M) }\left[\begin{matrix}A & -B & C\\ -D & E & -F\\ G & -H & I\end{matrix}\right]\]

Answer 7

Transpose the original matrix.
\[\left[\begin{matrix}4 & 2 & 5 \\ -1 &2 &-2\\ 1 & 3 & 6\end{matrix}\right]\]

Answer 8

A = \[\det \left[\begin{matrix}2 & -2 \\ 3 & 6\end{matrix}\right]\]

Answer 9

B = \[\det \left[\begin{matrix}-1& -2 \\ 1 & 6\end{matrix}\right]\]

Answer 10

C = \[\det \left[\begin{matrix}-1 & 2 \\ 1 & 3\end{matrix}\right]\]

Answer 11

D = \[\det \left[\begin{matrix} 2& 5 \\ 3 & 6\end{matrix}\right]\]

Answer 12

Do you see the pattern?

Answer 13

Thanks for your help but this is not the method I have been taught. So, even though I might understand it, I cannot use it...

Answer 14

You can solve the matrix by adjoining it with the identity or through this method. I did my linear algebra exam using this method.

Answer 15

I hope this helps to check your answers. It's a fast way to check because you're only computing 2x2 determinants

Answer 16

Thanks I'll keep that in mind...☺

Answer 17

Can Anybody show solution by adjoining the identity matrix...???

Answer 18

you can also solve it by row and column transformation method

Answer 19

we have not been taught that method