So in writing balanced equations I have a mixture of AgNO3 (Ag^+) and Na2CO3 (CO3^2), would I use AgNo3 and Na2CO3 or Ag^+ and CO3^2?
\[Ag^+ + NO_3^{-} \] similarly, \[Na^+ \] and \[CO_2^{2-}\] put togeher (+) and (-)
Sorry carbonate is: \[CO_3^{2-}\]
So how would I write a balanced equation for this,I am totally confused. I thought to get a balanced equation one would need to use the AgNO3 + Na2CO3 to get the product or am I wrong about this?
\[AgNO_3 + Na_2CO_3 \rightarrow NaNO_3 + Ag_2CO_3 \] Now, balance it. Notice there are now 2 silver's on the right, and one on the left. So you eed to fix that. Similarly, You have 2 sodiums on the left, but 1 on the right. If you still need help, let me know. Try to balance it with the information I just gave you though :)
It will be a minute for me.
Try it. I have time :)
would it look like this 2AgNO3 + NaCO3 → 2NaNO3 + Ag2CO3 does this look correct?
Yep! Looks correct to me!
Great it makes a little more sense, so to come up with the product of NaNO3 +Ag2CO3 I would need to know what is soluble and insoluble i.e (l, g, s, aq) and to use the rules of solubility, correct?
Yeah, there are rules, but I don't know them.
I found them and printed them off. So in order to write the net ionic equations I would use the same or the Ag+ and CO3^2-, or do I first need to figure out what is ionic and go from there?
and for your future reference here is the site I got them from http://www.ausetute.com.au/solrules.html
net ionic is just a chemical equation for a reaction which lists only those species participating in the reaction.
This is how you should proceed: 1. Start by simply writing the overall balanced chemical reaction. This is also called the Molecular Equation (which you already have and balanced out). 2. Then, you break apart the soluble molecules into the two ions that are formed (one positive and one negative). You will have to use the solubility rules to do this (which you also already found online!) If something is insoluble, it should NOT be broken apart. Write the reaction out with all of the separated ions. This is called the Total Ionic Equation. 3. Then, you simplify by canceling things out if they appear on both sides of the reaction, resulting in the Net Ionic Equation.
Alright I will give that a try, I will try to post again here really quick, I am going to reread the section of the text and then figure it out. Hopefully you will be on, maybe in an hour to see.
I probably will. Haha. I'm bored wasting time until night comes.
Ag→Ag₂
Na cancels out, NO3 cancels out, and NO3 this is what I had gathered after reading the text again.
Correct.
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