Mathematics
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OpenStudy (anonymous):
Rationalize the denominator of 6/(7-3 sqrt6)+(-2+2 sqrt6)
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OpenStudy (anonymous):
@NewOne
OpenStudy (anonymous):
Is it \[\frac{ 6 }{ 7-3\sqrt{6} }+\left( -2+2\sqrt{6} \right)\]
OpenStudy (anonymous):
it's all under the 6
OpenStudy (anonymous):
sorry. I need to get my math done by tomorrow and I'm worrying haha
OpenStudy (anonymous):
Ok what you do first is simplify the denominator as much as you can.
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OpenStudy (anonymous):
alright
OpenStudy (anonymous):
So what do you have as the denominator?
OpenStudy (anonymous):
6/5-1sqrt6?
OpenStudy (anonymous):
Yup, that's correct. Have you learned conjugates in class?
OpenStudy (anonymous):
yes! alright so times by (5+1sqrt6)?
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OpenStudy (anonymous):
Multiply it into the denominator and numerator.
OpenStudy (anonymous):
Then you're done
OpenStudy (anonymous):
30+sqrt6/25+sqrt 6...?
OpenStudy (anonymous):
30-6sqrt6/31?
OpenStudy (anonymous):
Uh.. no
Let's rewrite it so it's more clearer.
\[\frac{ 6 }{ 5-1\sqrt{6}}*\frac{ 5+1\sqrt{6} }{ 5+1\sqrt{6} }\]
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OpenStudy (anonymous):
Notice you're basically multiplying the fraction by 1
OpenStudy (anonymous):
so 30+6√6
OpenStudy (anonymous):
is the top
OpenStudy (anonymous):
Yup
OpenStudy (anonymous):
/19
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Whenever you are asked to rationalize, just remember to multiple the conjugate of the denominator to the top and bottom of the fraction