Question

Find a numerical value of one trigonometric function of csc x if sec x cot x = 4.? HELP...

Answer 1

(secx)(cotx)=4
(1/cosx)(cosx/sinx)=4----cancel out cosx by cosx u left with
1/sinx=4
cscx=4 that's it!!!

Answer 2

tan x/cot x - sec x/cos x = 2/csc x ?

Answer 3

thanks so much...but could you help me with that one???

Answer 4

@neba.zi

Answer 5

ok wait minite

Answer 6

I think I have to find the value of sin x

Answer 7

look cotx=1/tanx& cosx=1/secx substiute this valu
the u will get tan2x-sec2x=2sinx----then divide by2 both sides to find the valu of sinx(2 shows as square)

Answer 8

what do you mean?

Answer 9

so the answer is 2^2

Answer 10

or sqr2

Answer 11

Yes sqr2 the answer is (tanSqrx-secsqrx)/2 i think it is!!

Answer 12

thanks!

Answer 13

pleasure but is the value of sinx simply a number or.....I doubt sorry