Question

integral

Answer 1

@hartnn

Answer 2

\[\int\limits_{}^{}e^{-x^2}dx+\int\limits_{}^{}\sin(3x)dx\]

Answer 3

I agree with S0fw0n

Answer 4

Do you just want the anti-derivative or what?

Answer 5

i know that one already but how to integrate e^-x^2 lol

Answer 6

i know e^x is e^x but what if e^f(x)=?

Answer 7

To integrate \(e^{-x^2}\), you have to do a Maclaurin series expansion. I'm pretty sure it's transcendental.

Answer 8

ohk what about sin(3x)

Answer 9

You can't integrate using normal sense of integration. You would have to use taylor series for
\[e^{-x^2}\]

Answer 10

For \(\sin(3x)\), you have to use u-substitution. \(u = 3x\quad du = 3dx\).

Answer 11

ok thx

Answer 12

Are you sure that it has no bounds? Because I have seen this in quantum, but it's usually integrated from 0 to ∞