Question

The force between two charges Q and q is 0.000000031N. when the two charges are separated by 3.0m. using the formula F=kQq/r^2 determine the force (F) when the separation (R) between two charges Q and q is increased from 3m to 4.5m.

Answer 1

its under variation

Answer 2

since the distance changes from 3 to 4.5
\[\frac{ 4.5 }{ 3 } = 1.5\]
and \[(1.5)^2 \]
since it's: \[r^2\]
Meaning the force is decrease by a factor of 2.25
Hence,
\[\frac{ 3.1 \times 10^{-8} }{ 2.25 } = \]