Question

Please wait for image! Logarithms question.

Answer 1

Q10

Answer 2

\[\log(\frac{ 100\sqrt{p} }{ q^2 }) \]

Answer 3

i think you just plug in p for x and q for y.

Answer 4

\(\large log(\frac{100 \sqrt{x}}{y^2})=log(100 \sqrt{x})-log(y^2) \)
\(\large =log(100)+log( \sqrt{x})-log(y^2) \)
\(\large =2+logx^{(1/2)}-2logy \)
\(\large =2+\frac{1}{2}logx-2logy \)
\(\large =2+\frac{1}{2} \cdot p-2 \cdot q \)

Answer 5

You're supposed to help, not give out answers and solutions to show off!

Answer 6

ok... my bad...
can u do the second part?

Answer 7

The second expression is given as\[\log_{}y ^{x} \]Hence first simplify by applying the power property\[\log_{b}x ^{n}=n \log_{b}x \]

Answer 8

OK go ahead, even though I know you're being sarcastic @dpaInc

Answer 9

log \[y ^{x}\] = x log y

Answer 10

Yes! Now the objective of the question is to write the answer in terms of p and q. You already know what log y equals because its given. As far as the x is concerned, simply write log x = p (given) in exponential form.

Answer 11

okay, I'll try with that

Answer 12

Okay go ahead and show me your answer.

Answer 13

I just end up with xq and dont know how to continue

Answer 14

Did you read my explanation above? You're given that log x = p, right? What is log x = p in exponential form? Answer me this, first.

Answer 15

10^p = x?

Answer 16

If\[\log_{b}m =n \]then\[b ^{n}=m\]Thus how can log x = p be expressed in exponential form?

Answer 17

Yes!

Answer 18

So then what is your final answer now?

Answer 19

10^p(q) ?

Answer 20

Perfect! or you can also write it as q(10^p). Well done!

Answer 21

Alright, thanks :)

Answer 22

Welcome! Now you can tell @dpalnc that's how you teach!

Answer 23

@calculusfunctions But in all honesty, I personally have no problems with @dpaInc 's way of teaching...

Answer 24

@calculusfunctions, you got some beef with me? I already said it was my bad! get over it DH!